Lake Alfred, FL City Limits stuff
Lake Alfred is in Polk County, Florida, and covers 21.0 square miles.
Towns near Lake Alfred
Auburndale, FL (5 mi) Haines City, FL (6 mi) Winter Haven, FL (6 mi) Davenport, FL (7 mi) Polk City, FL (8 mi) Lake Hamilton, FL (8 mi)
Auburndale, FL (5 mi) Haines City, FL (6 mi) Winter Haven, FL (6 mi) Davenport, FL (7 mi) Polk City, FL (8 mi) Lake Hamilton, FL (8 mi)