Lake Alfred, FL City Limits stuff
Lake Alfred is in Polk County, Florida, covers 21.0 square miles, and had an estimated 8,632 residents in July 2024, per the US Census Bureau. The shirt carries the number from our original 2011 printing. Here's why we kept it.
Towns near Lake Alfred
Auburndale, FL (5 mi) Haines City, FL (6 mi) Winter Haven, FL (6 mi) Davenport, FL (7 mi) Polk City, FL (8 mi) Lake Hamilton, FL (8 mi)
Auburndale, FL (5 mi) Haines City, FL (6 mi) Winter Haven, FL (6 mi) Davenport, FL (7 mi) Polk City, FL (8 mi) Lake Hamilton, FL (8 mi)